Calculate the mass of iron, which will be convert, into its oxide(Fe3O4) by the action of 18g of steam on it

(A)21g (B)42g (C)64g (D)51g

well 18g of steam is 1 mole of H2O

So, write the balanced equation to see how many moles of Fe will be used. Then get the mass from that.

To calculate the mass of iron that will be converted into its oxide (Fe3O4) when 18g of steam reacts with it, we need to use the concept of stoichiometry.

First, let's write down the balanced chemical equation for the reaction between iron and steam to form Fe3O4:

3Fe(s) + 4H2O(g) -> Fe3O4(s) + 4H2(g)

From the balanced equation, we can deduce that 3 moles of iron react with 4 moles of steam to produce 1 mole of Fe3O4.

To find the mass of iron, we need to convert the mass of steam (18g) to moles. To do this, we need to know the molar mass of water (H2O), which is approximately 18g/mol.

18g H2O * (1 mol H2O / 18g H2O) = 1 mol H2O

According to the stoichiometry of the balanced equation, this means that 3 moles of iron (Fe) will react with these 1 mole of water (H2O) to produce 1 mole of Fe3O4.

Now, we can convert moles of Fe to grams using the molar mass of iron (Fe), which is approximately 56g/mol.

1 mol Fe * (56g Fe / 1 mol Fe) = 56g Fe

Therefore, 56g of iron will be converted into its oxide (Fe3O4) by the action of 18g of steam on it.

The correct answer is (D) 51g.