Two coins were tossed 10 times. The result is shown in the table below.
Toss: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10.
Result: 1)HH, 2)TT, 3)HT, 4)TH, 5)HT, 6)HH, 7) TH, 8)TT, 9) TH, 10) HT
What is the experimental probability that at least one of the coins landed on heads? Express the probability as a decimal.
A 0.8
B: 0.2*
C: 0.6
No. There were 10 tosses. 8 of them showed at least one H
So, P = 8/10 = 0.8
The answer the this specific question was 0.75.
you have it exactly backwards.
0.2 is the probability that NO heads showed.
Experimental probability means you go with the number of success in the experiment divided by the total number of trials.
Here success is defined as at least one of the coins landed on heads, i.e. includes HH, HT, TH.
Count the total number of the above outcomes and divide by 10 to get the experimental probability.
Hint: the only outcome excluded is TT. Here it is easier to count the number of failures (TT) and subtract from 10 to get the number of successes.
Oh my god I must be very dumb, I am so lost.
So am I supposed to add up the toss which gives me 55 and divide by 10?
Ohhh! I get it, I over thought it. Thank you so much for everyone who helped!
Two coins were tossed 10 times. The results are shown in the table.%0D%0A%0D%0A%0D%0AToss %091%092 %093 %094 %095 %096 %097 %098 %099 %0910 %0D%0AResult%09HH%09TT %09HT %09TH %09HT %09HH %09TH %09TT %09TH %09HT%0D%0A%0D%0AUse the table and information to answer the question.%0D%0A%0D%0A%0D%0A%0D%0A3. What is the experimental probability that at least one of the coins landed on heads? Express the probability as a decimal.
The experimental probability of at least one coin landing on heads is the number of successful outcomes (HH, HT, TH) divided by the total number of trials. We can see from the table that out of 10 tosses, only 1 toss resulted in no head (TT), meaning the other 9 tosses had at least one head. Therefore, the experimental probability is 9/10 or 0.9.
To find the experimental probability, you need to determine the number of times at least one of the coins landed on heads and divide it by the total number of trials. Let's count the number of times at least one coin landed on heads.
From the given data, the results in the following tosses include at least one head: 1, 3, 4, 5, 6, 7, 9, and 10.
Therefore, there are 8 out of 10 trials where at least one coin landed on heads.
To calculate the experimental probability, divide the number of trials where at least one coin landed on heads by the total number of trials:
Experimental probability = Number of trials with at least one head / Total number of trials
Experimental probability = 8 / 10
Simplifying, the experimental probability is 0.8.
So, the correct answer is A: 0.8.
Don't know you're under xx or "help! pls", but this question cannot have an answer of 0.75 because it deals with experimental probability, which bases it on the outcomes of the experiment.
However, the theoretical probability, which is the mathematical answer, is 0.75.