6. 7^5 • 7^6 = (1point)
a. 49^30
b. 7^30
c. 49^11***
d. 7^11
nope
7^5 * 7^6 = 7^(5+6) = 7^11
Better review the rules of exponents. The base does not change:
a^m * a^n = a^(m+n)
NOT
(a^2)^(m+n)
7^5 * 7^6
= 7*7*7*7*7 * 7*7*7*7*7*7
= 7^11
all 7's, no 49's
To solve this problem, we can use the rule of exponents which states that when you multiply two numbers with the same base, you add their exponents.
In this case, we have 7 raised to the power of 5 multiplied by 7 raised to the power of 6. Using the rule of exponents, we can add the exponents together:
7^5 • 7^6 = 7^(5+6) = 7^11
So, the answer is d. 7^11.