Concentrated HCl is 12.0M(mol/L) and you want to make a liter of 1.00 M HCl. What volume would you need of this concentrated solution so you would have one mole of HCl?
mL1 x M1 = mL2 x M2
mL1 x 12 = 1000 x 1
To determine the volume of the concentrated HCl solution needed to make a liter of 1.00 M HCl, we can use the formula:
M1 × V1 = M2 × V2
where M1 is the initial concentration, V1 is the initial volume, M2 is the final concentration, and V2 is the final volume.
In this case, we want to find V1, the initial volume of the concentrated HCl solution. We know that:
- M1 (concentrated HCl) = 12.0 M
- M2 (final concentration) = 1.00 M
- V2 (final volume) = 1.00 L (since we want to make a liter of 1.00 M HCl)
We can rearrange the formula to solve for V1:
V1 = (M2 × V2) / M1
Substituting the values we know:
V1 = (1.00 M × 1.00 L) / 12.0 M
V1 = 0.0833 L
Therefore, you would need approximately 0.0833 L (or 83.3 mL) of the concentrated HCl solution to make one mole of HCl in a liter of 1.00 M HCl.