In the hydraulic lift in the illustration, the car on the one side of the lift can be lifted by applying an effort force to the opposite side of the lift. If the effort force applied (F1) was 900 N on the 1 m2 area (A1), what is the load force of the car (F2) if the area (A2) is 15 m2
load is 15*900 N
To find the load force (F2) of the car, we can use the principle of Pascal's law which states that the pressure applied to a fluid in a closed system is transmitted equally in all directions.
In this case, the hydraulic lift is a closed system filled with fluid. The effort force (F1) is applied to a smaller area (A1), and we need to find the load force (F2) on the larger area (A2).
First, we need to calculate the pressure on the smaller area (P1) using the formula:
P1 = F1 / A1
Given F1 = 900 N and A1 = 1 m², we can substitute these values into the formula:
P1 = 900 N / 1 m² = 900 N/m²
Now, according to Pascal's law, this pressure will be transmitted equally and applied on the larger area (A2) as well. So, we can calculate the load force (F2) using the formula:
F2 = P1 * A2
Given A2 = 15 m², we can substitute the values:
F2 = 900 N/m² * 15 m² = 13,500 N
Therefore, the load force (F2) acting on the car is 13,500 N.