2x*9x^y9=
is it 18x^y^9+1??
this is my work
{(x, y) element R^2 : x>0 or (x = 0 and y>0)}
(d)/(dx)(2 x×9 x^(y^9)) = 18 (y^9 + 1) x^(y^9)
18 x^(1 + y^9) dx = (18 x^(y^9 + 2))/(y^9 + 2) +
quite a difference in your posts.
2x * 9x^(y^9))
= 18x^(y^9+1)
Now, taking the derivative of u^v is a combination of
d/dx a^v = lna a^v dv/dx
d/dx u^n = n u^(n-1) du/dx
d/dx u^v = v u^(v-1) u' + lnu u^v v'
Since we have u=x, and v=y^9+1, taking d/dx, we get
(y^9+1) x^(y^9) + lnx x^(y^9+1) y'
Not sure what the rest of the question is...
It seems like you have an equation: 2x * 9x^y9 = ?
To solve this equation, we need some clarification. Is there a specific value or variable we are trying to solve for? If not, we can simplify the expression.
First, let's break down the terms in the equation:
- The term 2x represents 2 multiplied by the variable x.
- The term 9x^y9 represents 9 multiplied by the variable x raised to the power of y9.
To simplify the expression, we can combine the terms by multiplying them together:
2x * 9x^y9 = 18x * x^y9
When multiplying variables with the same base, we add their exponents:
18x * x^y9 = 18x^(1+y9)
So, the simplified expression is 18x^(1+y9).
If you have a specific value for x and y9, you can substitute them into the expression and calculate the result. Otherwise, this is as far as we can simplify the equation without more information.