The solvent CCl4 is manufactured as follows CS2+Cl2=CCl4+S2Cl2. Balance it and calculate the grams of CS2 needed to react with 62.7 of Cl2?
CS2 + 3Cl2 => CCl4 + S2Cl2.
mols Cl2 = grams/molar mass = ?
Convert mols Cl2 to mols CS2 using the coefficients in the balanced equation.
Then grams CS2 = mols CS2 x molar mass CS2. Post your work if you get stuck.
To balance the given chemical equation, CS2 + Cl2 = CCl4 + S2Cl2, we must make sure that the number of atoms for each element is the same on both sides of the equation.
First, let's balance the carbon (C) atoms:
On the left side, there is one carbon atom in CS2, while on the right side, there is one carbon atom in CCl4. Carbon is already balanced.
Next, let's balance the sulfur (S) atoms:
On the left side, there is one sulfur atom in CS2, while on the right side, there are two sulfur atoms in S2Cl2. To balance the sulfur atoms, we need to multiply the CS2 on the left side by 2, resulting in:
2 CS2 + Cl2 = CCl4 + S2Cl2
Now, let's balance the chlorine (Cl) atoms:
On the left side, there are two chlorine atoms in Cl2, while on the right side, there are four chlorine atoms in CCl4. To balance the chlorine atoms, we need to multiply CCl4 on the right side by 2, resulting in:
2 CS2 + Cl2 = 2 CCl4 + S2Cl2
The balanced chemical equation is: 2 CS2 + Cl2 = 2 CCl4 + S2Cl2.
To calculate the grams of CS2 needed to react with 62.7 g of Cl2, we need to use stoichiometry.
Looking at the balanced equation, we see that the molar ratio between CS2 and Cl2 is 2:1. In other words, for every 2 moles of CS2, 1 mole of Cl2 is required.
1 mole of Cl2 has a molar mass of 70.91 g/mol.
To calculate the moles of Cl2, we divide the given mass of Cl2 by its molar mass:
Moles of Cl2 = 62.7 g Cl2 / 70.91 g/mol Cl2
Moles of Cl2 ≈ 0.883 mol Cl2
Now, using the molar ratio between CS2 and Cl2, we can calculate the moles of CS2:
Moles of CS2 = 0.883 mol Cl2 × (2 mol CS2 / 1 mol Cl2)
Moles of CS2 ≈ 1.766 mol CS2
Finally, to find the grams of CS2 needed, we multiply the moles of CS2 by its molar mass:
Grams of CS2 = 1.766 mol CS2 × 76.14 g/mol CS2
Grams of CS2 ≈ 134.6 g CS2
Therefore, approximately 134.6 grams of CS2 are needed to react with 62.7 grams of Cl2.