Imagine a conceptual representation of a math problem scenario in a non-textual form. Perhaps show three question marks symbolizing the three questions in the test, two are glowing or highlighted to represent the correct answers and one is dim or marked differently to represent the incorrect answer. Include an abstract representation of Mary - perhaps a stylized female figure drawn in an abstract manner. Please refrain from adding any actual text, numbers, or specific probabilities to the image.

There are 3 short questions on math test. for each question, 1 mark will be awarded for a correct answer and no mark for wrong answer. if the probability that mary correctly answers a question in a test is 2/3, determine the probability that mary correctly answers a question test is 2/3, determine the probability the probability that nary gets 2 marks in the test.

4/27

If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.

2/3 * 2/3 * 1/3 = ?

Well, Mary has a probability of 2/3 of answering a question correctly. So, the probability of her answering a question incorrectly would be 1 - 2/3 = 1/3.

To find the probability of Mary getting 2 marks on the test, we need to consider the different ways this can happen:

1. First question correct, second question correct, third question incorrect.
Probability: (2/3) * (2/3) * (1/3)

2. First question correct, second question incorrect, third question correct.
Probability: (2/3) * (1/3) * (2/3)

3. First question incorrect, second question correct, third question correct.
Probability: (1/3) * (2/3) * (2/3)

Now we add up the probabilities of these three scenarios to get the total probability of Mary getting 2 marks:

(2/3) * (2/3) * (1/3) + (2/3) * (1/3) * (2/3) + (1/3) * (2/3) * (2/3) = 12/81

Therefore, the probability that Mary gets 2 marks in the test is 12/81 or approximately 0.148.

To determine the probability that Mary gets 2 marks in the test, we need to consider the different possible scenarios.

Scenario 1: Mary answers 2 questions correctly and 1 question incorrectly.
The probability of Mary correctly answering a question is 2/3, and the probability of answering a question incorrectly is 1/3. Since there are 3 questions in total, the probability of this scenario is:

(2/3) * (2/3) * (1/3) = 4/27

Scenario 2: Mary answers all 3 questions correctly.
The probability of Mary correctly answering a question is 2/3. Since there are 3 questions in total, the probability of this scenario is:

(2/3) * (2/3) * (2/3) = 8/27

Scenario 3: Mary answers 1 question correctly and 2 questions incorrectly.
The probability of Mary correctly answering a question is 2/3, and the probability of answering a question incorrectly is 1/3. Since there are 3 questions in total, the probability of this scenario is:

(2/3) * (1/3) * (1/3) = 2/27

To find the probability that Mary gets 2 marks in the test, we need to add up the probabilities of scenarios 1 and 3:

4/27 + 2/27 = 6/27 = 2/9

Therefore, the probability that Mary gets 2 marks in the test is 2/9.

To determine the probability that Mary gets 2 marks in the test, we need to consider all possible combinations of correct and incorrect answers for the three questions.

Let's analyze the possible scenarios:

1. Mary answers all three questions correctly: The probability of this happening is (2/3)*(2/3)*(2/3) since each question has a 2/3 probability of being answered correctly. So, the probability for this scenario is (2/3)^3.

2. Mary answers two questions correctly and one question incorrectly: There are three ways this scenario can occur: CCI (correct, correct, incorrect), CIC (correct, incorrect, correct), or ICC (incorrect, correct, correct). The probability for each of these scenarios is (2/3)*(2/3)*(1/3) since one out of the three questions is answered incorrectly. Therefore, the overall probability for this scenario is 3 * (2/3)*(2/3)*(1/3).

3. Mary answers one question correctly and two questions incorrectly: Similar to the previous case, there are three ways this can occur: CII (correct, incorrect, incorrect), ICI (incorrect, correct, incorrect), or IIC (incorrect, incorrect, correct). The probability for each of these scenarios is (2/3)*(1/3)*(1/3) since only one out of the three questions is answered correctly. So, the overall probability for this scenario is 3 * (2/3)*(1/3)*(1/3).

4. Mary answers all three questions incorrectly: The probability of this happening is (1/3)*(1/3)*(1/3) since each question has a 1/3 probability of being answered incorrectly. So, the probability for this scenario is (1/3)^3.

To determine the probability that Mary gets 2 marks in the test, we need to add up the probabilities from scenarios 2 and 3 because those are the cases where she correctly answers two questions. Therefore, the final probability is:

Probability = (3 * (2/3)*(2/3)*(1/3)) + (3 * (2/3)*(1/3)*(1/3))

Simplifying,

Probability = (12/27) + (6/27)

Probability = 18/27

Simplifying further,

Probability = 2/3

Therefore, the probability that Mary gets 2 marks in the test is 2/3.