1. How many different lunch combinations can be made from three sandwich choices, two item choices, and four beverage choices if you choose one sandwich, one side, and one beverage?
9
20
24**
2.A bicycle manufacturer offers two styles , three sizes, and five different colors. How many different bicycles are offered?
30***
25
10
3. A restaurant offers four different appetizers, nine different entrees, and three different desserts. How many different meals can you order of one appetizer, one entrée and one dessert?
98
108***
120
1.A
2.B
3.C
4.A
5.B
Lesson 1: Counting Outcomes
Math 6 B Unit 5: Exploring Probability
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I HATE HOMESCHOOL
A little late, but if anyone else needs help, then here you go ///
Thanks Conexus!
i hate homeschool as well i am forced to do homeschool when i could've gone to real school.
I dislike homeschool, but at the same time, if your cheating you would probable be failing in real school.
So theres that.
All 3 are correct
thx:)))
Thx con nexus I finally get to go to bed lol
To answer these questions, we can use the concept of permutations.
1. For the first question, we have three sandwich choices, two item choices, and four beverage choices. To find the number of different lunch combinations, we need to multiply the number of choices for each category. In this case, we choose one option from each category, so we multiply 3 (sandwich choices) by 2 (item choices) by 4 (beverage choices). The result is 3 x 2 x 4 = 24. Therefore, the correct answer is 24.
2. For the second question, we have two styles, three sizes, and five colors. To find the number of different bicycles offered, we need to multiply the number of choices for each category. In this case, we choose one option from each category, so we multiply 2 (styles) by 3 (sizes) by 5 (colors). The result is 2 x 3 x 5 = 30. Therefore, the correct answer is 30.
3. For the third question, we have four appetizer choices, nine entree choices, and three dessert choices. To find the number of different meals that can be ordered, we need to multiply the number of choices for each category. In this case, we choose one option from each category, so we multiply 4 (appetizer choices) by 9 (entree choices) by 3 (dessert choices). The result is 4 x 9 x 3 = 108. Therefore, the correct answer is 108.