Rohit is twice as old as roshni.5 years ago his age was three times roshni age.find their present ages
x = Rohit's age now
y = Roshni's age now
x = 2y
x-5 = 3(y-5)
Now just solve for x and y
X=2y
X-5=3(y-5)
To find Rohit and Roshni's present ages, we can set up a system of equations.
Let's assume Rohit's present age is represented by R, and Roshni's present age is represented by H.
According to the given information, "Rohit is twice as old as Roshni," we can write:
R = 2H (Equation 1)
We are also told that "5 years ago, Rohit's age was three times Roshni's age." This can be expressed as:
(R - 5) = 3(H - 5) (Equation 2)
To find their present ages, we need to solve these two equations simultaneously.
Let's substitute Equation 1 into Equation 2:
(2H - 5) = 3(H - 5)
Expanding the equation, we get:
2H - 5 = 3H - 15
Rearranging the terms, we get:
3H - 2H = 15 - 5
H = 10
Now, we know Roshni's present age is 10.
Using Equation 1, we can find Rohit's present age:
R = 2H
R = 2 * 10
R = 20
Therefore, Roshni's present age is 10, and Rohit's present age is 20.