Calculus Please Check my answer

posted by Dloc

Set up, but do not evaluate, the integral which gives the volume when the region bounded by the curves y = Ln(x), y = 1, and x = 1 is revolved around the line y = -1.
ANSWER:

v = ∫[1,e] π(4-(lnx+1)^2) dx

  1. Steve

    looks good to me. Or, using shells,

    v = ∫[0,1] 2π(y+1)(e^y-1) dy

  2. Dloc

    thank you!

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