A MACHINE HASA VELOCITYRATIO5 IS 80% EFFICIENT. WHAT EFFORT WOULDNEEDED TO LIFT A LOAD OF200N WITH THEAIDOFTHIS MACHINE
.8=effort/200
effort=160N
To determine the effort needed to lift a load of 200N with the aid of this machine, we need to consider the concepts of velocity ratio and efficiency.
The velocity ratio is the ratio of the distance moved by the effort to the distance moved by the load. In this case, the velocity ratio is given as 5.
Efficiency is the ratio of output work to input work for a machine, expressed as a percentage. In this case, the machine is stated to be 80% efficient.
To calculate the effort needed, we can use the formula:
Efficiency = (Output Work / Input Work) * 100
Since we know the efficiency is 80%, we can rewrite the formula as:
80 = (Output Work / Input Work) * 100
To find the effort, we need to calculate the input work.
Input Work = Output Work / Efficiency
In this case, the output work is equal to the weight of the load multiplied by the distance it moves. Since the distance is not given, we can assume that the distance moved by the effort is 1 unit, and the distance moved by the load is 5 units (based on the velocity ratio of 5).
Output Work = 200N * 5 = 1000N (assumed distance = 5 units)
Now we can calculate the input work:
Input Work = Output Work / Efficiency
Input Work = 1000N / 0.8 = 1250N
Finally, the effort needed to lift the load of 200N with the aid of this machine is 1250N.