Tshepo is five years older than two times Tanya's age. Jake is three times as old as Tshepo. If Jake is forty five, then how old are Tshepo and Tanya?

Tanya ---- x

Tshepo ---- 2x+5
jake = 3(2x+5)

solve:
3(2x+5) = 45

then sub the value of x into my definitions.
What did you get?

Tanya = 5

Tshepo = 15

Thank you for the help Reiny.

To find the ages of Tshepo and Tanya, let's break down the information given in the question:

1. Tshepo is five years older than two times Tanya's age: We can represent this as Tshepo = 2*Tanya + 5.
2. Jake is three times as old as Tshepo: We can represent this as Jake = 3*Tshepo.

From the second statement, we are given that Jake is 45 years old. Therefore, we substitute this value into the equation Jake = 3*Tshepo:

45 = 3*Tshepo

To find Tshepo's age, we can divide both sides of the equation by 3:

Tshepo = 45/3
Tshepo = 15

Now that we know Tshepo's age is 15, we can substitute this value into the equation Tshepo = 2*Tanya + 5 to solve for Tanya's age:

15 = 2*Tanya + 5

Subtracting 5 from both sides of the equation:

10 = 2*Tanya

To find Tanya's age, we can divide both sides of the equation by 2:

Tanya = 10/2
Tanya = 5

So, Tshepo is 15 years old, and Tanya is 5 years old.