a block and tackle with a velocity ratio f 5 is used to raise a mass of 25kg through a vertical distance of 40cm at a steady rate.if the effort is equal to 60N .Determine 1.)the distance moved by he effort 2.)the work done by the effort in lifting the load 3.)the loss in energy involved in operating the machine
NO
To solve this problem, we need to understand the concepts of velocity ratio, work, and energy.
1) Distance moved by the effort:
The velocity ratio (VR) is defined as the ratio of the distance moved by the effort to the distance moved by the load. In this case, the VR is given as 5.
So, the distance moved by the effort (d_e) is:
d_e = VR * distance moved by the load
The distance moved by the load is given as 40 cm. Therefore:
d_e = 5 * 40 cm
d_e = 200 cm
Hence, the distance moved by the effort is 200 cm.
2) Work done by the effort:
Work is defined as the force applied over a distance. The formula for work is:
Work = Force * Distance
In this case, the force applied by the effort (F_e) is given as 60 N. And the distance moved by the effort (d_e) is 200 cm (which can also be converted to meters by dividing by 100).
Therefore:
Work = F_e * d_e
Work = 60 N * 200 cm / 100
Work = 12000 Ncm
Work = 120 Nm (since 1 Nm = 1 J)
Hence, the work done by the effort in lifting the load is 120 J.
3) Loss in energy involved in operating the machine:
The loss in energy refers to any energy that is not transferred to the load but is instead wasted or converted to other forms (e.g., heat, sound, friction losses).
In an ideal scenario, the loss would be zero. However, in real machines, losses are inevitable due to factors like friction.
To determine the loss in energy, we need to calculate the input energy (E_in) and the output energy (E_out). The loss in energy (E_loss) can be calculated as:
E_loss = E_in - E_out
Since the input energy is equal to the work done by the effort (as calculated in question 2), we can use that value.
The output energy can be determined as the product of the load force and the distance moved by the load (d_l):
E_out = Load force * d_l
The load force (F_l) can be calculated using the formula:
F_l = Effort force / VR
Therefore:
F_l = 60 N / 5
F_l = 12 N
And the distance moved by the load (d_l) is given as 40 cm.
So:
E_out = 12 N * 40 cm / 100
E_out = 4.8 Nm = 4.8 J
Now, we can calculate the loss in energy (E_loss):
E_loss = E_in (as calculated in question 2) - E_out
E_loss = 120 J - 4.8 J
E_loss = 115.2 J
Hence, the loss in energy involved in operating the machine is 115.2 J.