pls when solving finish it up!!! Very urgent!

1) the load which a crame can lift up is directly proportional to the mass and inversely proportional to the height through which the load is to be lifted.if a load of 40 and mass of 175gm is lifted through height from what load will be carried through height of 50m given the mass as 250gm?

Problem statement makes no sense to me. The heavier it is the more I can lift?

you still have not given the first height.

To solve the given problem, we can use the formula for direct and inverse proportionality:

Load ∝ (Mass/Height)

We can rewrite this as:

Load = k * (Mass/Height)

where k is the constant of proportionality.

To find the value of k, we can use the given information. When the load is 40 and the mass is 175g, we can substitute these values into the equation:

40 = k * (175/Height)

To solve for k, we need to isolate it on one side of the equation:

k = 40 * (Height/175)

Now that we have the value of k, we can use it to find the load when the mass is 250g and the height is 50m:

Load = k * (Mass/Height)
Load = (40 * (Height/175)) * (250/50)

Simplifying further:

Load = (40/175) * 250
Load = 8 * 10
Load = 80

Therefore, the load that can be carried through a height of 50m, with a mass of 250g, is 80 units.