Regular triangular pyramid has the slant height k=12 cm and lateral area A = 198 cm2. Find the length of the base edge.
Hi peeps!
How you do the problem is you do is you know that because its a regular triangle pyramid all sides are congruent so Al= 1/2 Pb*k.
So you plug in the numbers and the answer you get is 198=1/2*3*Ab*12
and in the end the answer you get is 11cm!
Hope this helped!
3 congruent triangles make up the 3 sides
the area of a side is ... 198 / 3 cm^2
the slant height is the height of a triangular side
you have the area and the height of a triangle ... how do you find the base length?
Ahh thank you so much Nado!!!!
A = 1/2 * b * h
how to find the area with a slant.
Nice
Would you multiply by 2
To find the length of the base edge of a regular triangular pyramid, we need to use the given information, which is the slant height (k) and the lateral area (A).
A regular triangular pyramid has a base that is an equilateral triangle. The lateral area formula for a regular triangular pyramid is given by:
A = (1/2) × perimeter of the base × slant height
Since the base is an equilateral triangle, the perimeter of the base (P) is equal to 3 times the length of one side (s).
Therefore, we can rewrite the lateral area formula as:
A = (1/2) × 3s × k
Now, let's substitute the given values into the formula:
198 = (1/2) × 3s × 12
To solve for the length of the base edge (s), we can rearrange the equation as follows:
198 = (3/2) × 12s
Divide both sides of the equation by 3:
198/3 = 12s/2
66 = 6s
Divide both sides of the equation by 6:
66/6 = s
11 = s
Therefore, the length of the base edge is 11 cm.