How many moles of O2 are contained in 5.25 L at 26 degrees Celsius and 1.2 atm?
PV=nRT
Solve for n = number of mols.
Don't forget T must be in kelvin.
To find the number of moles of a gas, we can use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.
First, let's convert the given temperature from degrees Celsius to Kelvin. The Kelvin temperature is equal to the Celsius temperature plus 273.15. So, the temperature in Kelvin is 26 + 273.15 = 299.15 K.
Next, let's convert the given pressure from atm to units of Pascals (Pa). Since 1 atm = 101325 Pa, the pressure in Pa is 1.2 x 101325 = 121590 Pa.
Now, we can rearrange the ideal gas law equation to solve for the number of moles (n):
n = PV / RT
n = (121590 Pa) x (5.25 L) / [(0.0821 L·atm/mol·K) x (299.15 K)]
Calculating this equation will give us the number of moles of O2 in 5.25 L at 26 degrees Celsius and 1.2 atm.