If an architect made a drawing of a swimming pool with a length of 15 inches and width of 4 inches. And the scale she used is 1 inch= 3.5 feet, what are the actual dimensions of the swimming pool?
15 * 3.5 = ______ feet
4 * 3.5 = ________ feet
If a pool measures 30 feet by 66 feet, what is the scale of the drawing shown?
To find the actual dimensions of the swimming pool, we need to convert the measurement on the drawing to the real-life scale.
The given scale is 1 inch = 3.5 feet.
First, let's calculate the length of the swimming pool using the scale:
Drawing Length / Scale = Actual Length
15 inches / 1 inch = 15 inches
15 inches * 3.5 feet = 52.5 feet
So, the actual length of the swimming pool is 52.5 feet.
Now, let's calculate the width of the swimming pool using the scale:
Drawing Width / Scale = Actual Width
4 inches / 1 inch = 4 inches
4 inches * 3.5 feet = 14 feet
Therefore, the actual width of the swimming pool is 14 feet.
Thus, the actual dimensions of the swimming pool are 52.5 feet (length) and 14 feet (width).