A man spends 1/2 of his salary on fees.2/3 on rent and rest on food. if he spends sh40,000 on food.What is the man's salary?
Let his salery be x then,total expendiature=salery.so,x.1/2+x/2.2/3+40000=x now by solving the equation, we get x=24000.
To find the man's salary, we need to determine how much he spends on fees and rent.
Let's assume the man's salary is represented by 'S'.
We know that the man spends 1/2 of his salary on fees, which can be calculated as (1/2)S.
We also know that he spends 2/3 of his salary on rent, which can be calculated as (2/3)S.
Finally, we are given that the man spends sh40,000 on food.
Since the amount spent on food is the remaining amount after fees and rent, we can set up the equation:
(1/2)S + (2/3)S + 40,000 = S
To solve this equation, let's multiply everything by the least common multiple of 2 and 3, which is 6:
(6 * 1/2)S + (6 * 2/3)S + 6 * 40,000 = 6S
3S + 4S + 240,000 = 6S
7S + 240,000 = 6S
Subtracting 6S from both sides gives:
S + 240,000 = 0
Subtracting 240,000 from both sides gives:
S = -240,000
However, since a salary cannot be negative, it seems there might be an error or missing information in the problem. Please double-check the values given or provide any additional information if available.