An experiment requires 0.3 M NH3(aq). The

stockroom manager estimates that 15 L of
the base is needed. What volume of 15 M
NH3(aq) will be used to prepare this amount
of 0.3 M base?
Answer in units of mL

To find the volume of 15 M NH3(aq) needed to prepare 0.3 M NH3(aq), you can use the equation:

M1 * V1 = M2 * V2

Where:
M1 = Initial concentration of NH3(aq)
V1 = Initial volume of NH3(aq)
M2 = Final concentration of NH3(aq)
V2 = Final volume of NH3(aq)

In this case, M1 = 15 M, M2 = 0.3 M, V2 = 15 L, and we need to find V1.

Rearranging the equation, we get:

V1 = (M2 * V2) / M1

Substituting the given values, we have:

V1 = (0.3 M * 15 L) / 15 M

Simplifying further:

V1 = 0.3 L = 300 mL

Therefore, the volume of 15 M NH3(aq) needed to prepare 0.3 M NH3(aq) is 300 mL.

L1 x M1 = L2 x M2

15L x 0.3M = L2 x 15M
L2 = ?