A mother is 33 years older than her twin children. In 3 years her age will be twice the combined ages of the twins. How old are the twins now?

HELPPPPPPPPPP!!!!!!!

age of each of the twins --- x

mother's age = x+33

In 3 years from now:
age of each of the twins = x+3
mother's age = x+36

x+36= 2(x+3 + x+3)

solve for x, and sub into my definitions

x=8

p.s. i made a mistake at first and thought the answer was six. hg is me. I wrote the 6 right above this.
thanks for reading :)

To solve this problem, we can start by assigning variables for the ages of the twins. Let's say T represents the age of one of the twins. Since the mother is 33 years older than the twins, her age would be T + 33.

Now, let's look at the second statement in the problem. In 3 years, the mother's age will be twice the combined ages of the twins. This can be written as (T + 33) + 3 = 2((T + 3) + (T + 3)).

Simplifying this equation, we have T + 36 = 2(2T + 6).

Distributing the multiplication on the right side of the equation, we get T + 36 = 4T + 12.

Next, we can subtract T from both sides of the equation to isolate the variable. This gives us 36 = 3T + 12.

Subtracting 12 from both sides, we have 24 = 3T.

Finally, we can divide both sides by 3 to solve for the value of T. This gives us T = 8.

Therefore, the twins are currently 8 years old.