If f(x)=∫[1,x^2] t^t dt
find f'(x).
Another problem similar to this one on my assignment was f(x)=∫[1,x] t^t dt, and the answer was f'(x)=x^x. That same pattern would say this answer should be (x^2)^(x^2), but that's not being accepted. What am I missing here? Please help
You forgot the chain rule. The result is
(x^2)^(x^2) * 2x
if f(x)=∫[1,u] t^t dt
and u = u(x) then
f'(x) = f(u) * du/dx