What is the morality of a solution made by dissolving 9.80 g of H2SO4 in a 200.0 g of H2O?
I think you mean molarity.
Yes sorry auto correct
Molality*
Actually, I think your meant Molality as in
m molality= molessolute/kg solvent
= (9.80/98)/.2 = 0.5m
The pitfalls of using your phone to post questions!!
Relying on autocorrect or not proofreading before posting are HUGE mistakes.
To determine the morality of a solution made by dissolving a certain amount of solute in a given amount of solvent, you need to know the mole ratio of the solute to the solvent.
In this case, you are given that 9.80 g of H2SO4 is dissolved in 200.0 g of H2O. To find the morality, you first need to convert the mass of H2SO4 to moles. The molar mass of H2SO4 is 98.09 g/mol, so you can use the formula:
moles of H2SO4 = mass of H2SO4 / molar mass of H2SO4
moles of H2SO4 = 9.80 g / 98.09 g/mol = 0.10 mol
Next, you need to find the moles of H2O. The molar mass of H2O is 18.015 g/mol, so you can use the formula:
moles of H2O = mass of H2O / molar mass of H2O
moles of H2O = 200.0 g / 18.015 g/mol = 11.10 mol
Now that you know the moles of H2SO4 and H2O, you can find the mole ratio by dividing the moles of H2SO4 by the moles of H2O:
mole ratio = moles of H2SO4 / moles of H2O
mole ratio = 0.10 mol / 11.10 mol = 0.009
The mole ratio represents the number of moles of solute (H2SO4) per mole of solvent (H2O). In this case, the mole ratio is 0.009.
Finally, to find the morality, you multiply the mole ratio by a factor of 1000 to convert it to millimoles per kilogram (which is the unit of morality):
morality = mole ratio * 1000
morality = 0.009 * 1000 = 9 mmol/kg
Therefore, the morality of the solution made by dissolving 9.80 g of H2SO4 in 200.0 g of H2O is 9 mmol/kg.