The rod of the fixed hydraulic cylinder is moving to the left with a speed of 100 mm/s and this speed is momentarily increasing at a rate of 400 mm/s each second at the instant when sA = 425 mm. Determine the tension in the cord at that instant. The mass of slider B is 0.5 kg, the length of the cord is 1050 mm, and the effects of the radius and friction of the small pulley at A are negligible. Find results for cases (a) negligible friction at slider B and (b) μk = 0.40 at slider B. The action is in a vertical plane.

First, let us analyze the problem and determine the governing equations for both cases.

Case (a) Negligible friction at slider B:

For this case, the tension in the cord (T) will be the force acting on the slider B due to its acceleration. First, we need to find the displacement of slider B (sB), which can be calculated from the given data.

sB = cord length - sA
sB = 1050 mm - 425 mm
sB = 625 mm

Now we need to determine the acceleration of the rod (aA) using the given data.

aA = rate of increase of the rod's speed
aA = 400 mm/s²

Since the cord length is constant, the acceleration of the slider B (aB) can be determined by multiplying the acceleration of the rod by the ratio of the lengths of the rod and the cord.

aB = aA * (sB / sA)
aB = 400 mm/s² * (625 mm / 425 mm)
aB = 588.24 mm/s²

Now we can calculate the tension in the cord using the mass of the slider B and its acceleration.

T = mass of slider B * acceleration of slider B
T = 0.5 kg * 588.24 mm/s²
T = 294.12 N

Therefore, the tension in the cord is 294.12 N for case (a).

Case (b) μk = 0.40 at slider B:

For this case, there will be a friction force (F_f) acting on the slider B in addition to the tension in the cord. We need to find the net force acting on the slider B (F_net) and then determine the tension in the cord accordingly.

First, let us determine the friction force using the given coefficient of kinetic friction (μk).

F_f = μk * mass of slider B * g
F_f = 0.40 * 0.5 kg * 9.81 m/s²
F_f = 1.962 N

Now we can determine the net force acting on the slider B.

F_net = mass of slider B * acceleration of slider B
F_net = 0.5 kg * 588.24 mm/s²
F_net = 294.12 N

Finally, we can calculate the tension in the cord for case (b) by subtracting the friction force from the net force acting on the slider B.

T = F_net - F_f
T = 294.12 N - 1.962 N
T = 292.16 N

Therefore, the tension in the cord is 292.16 N for case (b).

To determine the tension in the cord at the given instant, we can use Newton's second law and the principles of kinematics. Let's break down the problem into two cases: (a) negligible friction at slider B and (b) μk = 0.40 at slider B.

Case (a): Negligible friction at slider B
In this case, we assume that there is no friction at slider B, which means there are no external forces acting on slider B other than the tension in the cord.

Step 1: Find the acceleration of the rod
Given that the speed of the rod is increasing at a rate of 400 mm/s each second, we can find the acceleration.

Acceleration (a) = 400 mm/s^2

Step 2: Find the net force on slider B
Using Newton's second law (F = ma), we can find the net force acting on slider B.

Mass (m) = 0.5 kg
Acceleration (a) = 400 mm/s^2

Net Force (F) = m * a
F = 0.5 kg * 400 mm/s^2

Step 3: Find the tension in the cord
We can consider the forces acting on slider B. The tension force (T) in the cord and the weight force (mg) acting downwards. Since the slider B is in equilibrium, the net force on it is zero.

Net Force (F) = T - mg = 0

Since the rod is in a vertical plane, the weight force (mg) is acting downwards.

Weight Force (mg) = m * g

Where g is the acceleration due to gravity. We assume g = 9.8 m/s^2.

Now we can solve for T.

T = mg
T = 0.5 kg * 9.8 m/s^2

Convert mm to m:
1 mm = 0.001 m
T = 0.5 kg * 9.8 m/s^2 * (0.425 m / 1 mm)

Case (b): μk = 0.40 at slider B
In this case, there is kinetic friction at slider B, and we need to account for this additional force.

Step 1: Find the acceleration of the rod
The procedure for finding the acceleration remains the same as in Case (a). The acceleration of the rod is 400 mm/s^2.

Step 2: Find the net force on slider B
In this case, there are additional forces due to kinetic friction. The net force acting on slider B is the difference between the tension force and the force of kinetic friction.

Net Force (F) = T - μk * mg
F = 0

Step 3: Find the tension in the cord
We can solve for T in the same way as in Case (a).

T - μk * mg = 0

Solving for T:

T = μk * mg

Substituting the given values and converting mm to m:

T = 0.40 * 0.5 kg * 9.8 m/s^2 * (0.425 m / 1 mm)

So, to determine the tension in the cord at the given instant, you can use the above formulas and substitute the appropriate values for each case.

To determine the tension in the cord at the given instant, we need to analyze the forces acting on the system. Let's break it down into steps:

Step 1: Calculate the acceleration of the rod
We are given that the speed of the rod is increasing at a rate of 400 mm/s each second and that the rod's speed is initially 100 mm/s. Thus, the acceleration of the rod can be calculated as follows:
Acceleration = (final speed - initial speed) / time taken
Acceleration = (100 + 400 × time) / time, where time is in seconds.

Step 2: Determine the tension in the cord for case (a) negligible friction
In this case, we assume there is no friction at slider B. Therefore, the tension in the cord is given by the equation:
Tension = mass × (acceleration + gravitational acceleration)
Gravitational acceleration ≈ 9.8 m/s² (approximately)

Step 3: Determine the tension in the cord for case (b) with friction (μk = 0.40)
In this case, we consider the effect of friction at slider B. The tension in the cord will need to overcome the frictional force. The equation for tension with friction is:
Tension = mass × (acceleration + opposing force due to friction)

To determine the opposing force due to friction, we can use the equation:
Opposing force due to friction = coefficient of kinetic friction × Normal force
The normal force can be calculated as:
Normal force = mass × gravitational acceleration

Once we have the opposing force due to friction, we can substitute it into the tension equation.

Step 4: Calculate the tension in the cord at sA = 425 mm
Firstly, convert the length of the cord into meters (1050 mm = 1.05 m).
Substitute the known values into the appropriate equations derived from steps 2 and 3 to find the tension in the cord at sA = 425 mm for both cases (a) and (b).

Remember to pay attention to units and convert them if necessary.

Note: Since the question does not provide a specific time or rate of change, we cannot determine the exact tension at that instant.