3.65 g of HCl are dissolved in 2lit of the solution find the polarity
To determine the polarity of a molecule or compound, we need to consider its molecular geometry and the electronegativity difference between the atoms involved.
First, let's look at the molecule HCl. Hydrogen chloride (HCl) is a diatomic molecule consisting of a hydrogen atom and a chlorine atom. Chlorine is more electronegative than hydrogen, so it pulls the shared electron pair towards itself, creating a polar covalent bond. As a result, the chlorine atom becomes partially negative (δ-) and the hydrogen atom becomes partially positive (δ+).
Now, let's consider the solution that contains 3.65 g of HCl in 2 liters. We can calculate the molarity of the solution to determine its concentration. The molarity (M) is calculated using the formula:
Molarity (M) = Moles of solute / Volume of solution (in liters)
To find the number of moles, we need to divide the mass of HCl by its molar mass. The molar mass of hydrogen chloride (HCl) is approximately 36.5 g/mol (1 g/mol for hydrogen and 35.5 g/mol for chlorine).
So, the number of moles of HCl in the solution is:
Moles of HCl = Mass of HCl / Molar mass of HCl
Moles of HCl = 3.65 g / 36.5 g/mol
Next, we can calculate the molarity:
Molarity (M) = Moles of HCl / Volume of solution
Molarity (M) = (3.65 g / 36.5 g/mol) / 2 L
By performing this calculation, we can find the molarity of the solution.
Once we know the nature of the molecule (polar or nonpolar), we can determine the overall polarity of the solution. Since HCl is a polar molecule and it is completely dissolved in the solution, it will also make the solution polar.
Therefore, the solution containing 3.65 g of HCl in 2 liters of solution is polar.
Good Lord.
Molarity=molesHCl/2=3.65/(molemassHCl*2)