Driving in your car with a constant speed of v= 22 m/s, you encounter a bump in the road that has a circular cross-section, as indicated in the figure (Figure 1) .

Part A
If the radius of curvature of the bump is 52 m, find the apparent weight of a 66-kg person in your car as you pass over the top of the bump.

I hate physics

bababooey

...............................thx 4 the help

ok but why

just why

lol u put 12m/s instead of 22m/s

Ava wants to figure out the average speed she is driving. She starts checking her car’s clock at mile marker 0. It takes her 4 minutes to reach mile marker 3. When she reaches mile marker 6, she notes that 8 minutes total have passed since mile marker 0.

What is the average speed of the car in miles per minute?
mile(s) per minute
What is an equation of the line that represents n, the number of mile marker passed, as a function of t, time in minutes?

Help me plz

To find the apparent weight of the person in the car as it passes over the bump, we need to consider the forces acting on the person at that moment.

1. First, we need to determine the acceleration experienced by the person at the top of the bump. Since the car is moving with constant speed, the only acceleration acting on the person is the centripetal acceleration.

Centripetal acceleration (ac) can be calculated using the formula: ac = v^2 / r
where v is the velocity and r is the radius of curvature.

Given:
v = 22 m/s (constant speed)
r = 52 m (radius of curvature)

Plugging in the values, we get:
ac = (22 m/s)^2 / 52 m

2. Once we have the centripetal acceleration, we can find the net force acting on the person at the top of the bump.

The net force (F_net) is equal to the mass of the person multiplied by the acceleration:
F_net = m * ac
where m is the mass of the person.

Given:
m = 66 kg (mass of the person)
ac = calculated from step 1

Plugging in the values, we get:
F_net = 66 kg * ac

3. Finally, the apparent weight of the person can be calculated using Newton's second law which states that the net force acting on an object equals its mass multiplied by its acceleration.

Apparent weight (W_apparent) is equal to the net force:
W_apparent = F_net
where F_net is calculated from step 2.

To find the apparent weight, substitute the value of F_net from step 2 into the equation:
W_apparent = 66 kg * ac

Calculate the value of W_apparent using the given values and the previously calculated centripetal acceleration.

While the car is driving on the bump, a centripetal acceleration acts toward the center of the radius of curvature. Take the direction toward the center as positive, this is also the direction of the weight of the person. The apparent weight of the person will be equal to the normal force. From Newton's 2nd law:

∑F(c) = ma(c) = mg - n
n = mg - ma(c)

But a(c), centripetal acceleration, is equal to v²/r, so:

n = mg - mv²/r
= m(g - v²/r)
= 67kg[9.8m/s² - (12m/s)²/35m]
= 380N (properly rounded)

Hope this helps.