equation in graphing form: f(x)=(x+3)^2+2
original equation: f(x)=x^2+6x+ 11
state the vertex??
the "graphing form" is the vertex form
f(x) = a (x - h)^2 + k
... a = 1 in this case
vertex is (h,k)
original equation: f(x)=x^2+6x+ 11
state the vertex??
f(x) = a (x - h)^2 + k
... a = 1 in this case
vertex is (h,k)