(x+1)(x(-4-5i))(x-(4+5i))?
You know that (a-b)(a+b) = a^2-b^2 (a-bi)(a+bi) = a^2+b^2 So, (x+1)(x(-4-5i))(x-(4+5i)) = (x+1)((x-4)-5i)((x-4)+5i) = (x+1)((x-4)^2 - (5i)^2) = (x+1)(x^2-8x+16 + 25) = (x+1)(x^2-8x+41) = x^3-7x^2+33x+41 =
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