There are four different kinds of animals on the farm. There is a different number of each kind of animal. There are 19 more cows than sheep. There are 19 more ducks than hens. There are more hens than cows
What is the answer
What is the question?
To solve this problem, let's assign variables to each kind of animal. Let's use:
C = number of cows
S = number of sheep
D = number of ducks
H = number of hens
From the given information, we can create the following equations:
1) C = S + 19 (There are 19 more cows than sheep)
2) D = H + 19 (There are 19 more ducks than hens)
3) H > C (There are more hens than cows)
Since we have four different kinds of animals on the farm, we know that C, S, D, and H are all whole numbers.
Now let's solve for the values of C, S, D, and H. We can start by simplifying equation 3).
From equation 1), we can express S in terms of C:
S = C - 19
Substituting this into equation 3):
H > C
H > (C - 19)
Now we have two equations:
1) D = H + 19
2) H > (C - 19)
We need to find values for C, S, D, and H that satisfy these equations and the given conditions.
Let's try a few possible solutions and see which ones satisfy the conditions:
1) Let's assume C = 1.
From equation 1), we get S = 1 - 19 = -18, which is not a valid number of animals.
So, this solution does not work.
2) Let's assume C = 2.
From equation 1), we get S = 2 - 19 = -17, which is not a valid number of animals.
So, this solution does not work.
3) Let's assume C = 3.
From equation 1), we get S = 3 - 19 = -16, which is not a valid number of animals.
So, this solution does not work.
4) Let's assume C = 4.
From equation 1), we get S = 4 - 19 = -15, which is not a valid number of animals.
So, this solution does not work.
5) Let's assume C = 5.
From equation 1), we get S = 5 - 19 = -14, which is not a valid number of animals.
So, this solution does not work.
6) Let's assume C = 6.
From equation 1), we get S = 6 - 19 = -13, which is not a valid number of animals.
So, this solution does not work.
7) Let's assume C = 7.
From equation 1), we get S = 7 - 19 = -12, which is not a valid number of animals.
So, this solution does not work.
8) Let's assume C = 8.
From equation 1), we get S = 8 - 19 = -11, which is not a valid number of animals.
So, this solution does not work.
9) Let's assume C = 9.
From equation 1), we get S = 9 - 19 = -10, which is not a valid number of animals.
So, this solution does not work.
10) Let's assume C = 10.
From equation 1), we get S = 10 - 19 = -9, which is not a valid number of animals.
So, this solution does not work.
It seems that none of the assumptions for the number of cows (C) lead to valid solutions for the number of sheep (S). It's possible that this problem does not have a valid solution given the conditions provided.
Therefore, without further information, we cannot determine the exact values for the number of animals on the farm.