Air trapped in a cylinder fitted with a piston occupies 162.2 mL at 1.08 atm pressure. What is the new volume when the piston is depressed, increasing the pressure by 25%?
what is the answer? didnt understand?
That won't get it. We HELP you do your homework; we don't do it for you. I told you how to work the problem. If you don't understand, show what you've done or explain what it is you don't understand. I'll be glad to help you through it but I won't do it for you. Same thing for you post above using Charles' Law.
To solve this problem, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional at constant temperature.
We are given the initial volume of the trapped air in the cylinder as 162.2 mL and the initial pressure as 1.08 atm. We need to find the new volume when the pressure increases by 25%.
To determine the new volume, we need to use the formula:
P1 × V1 = P2 × V2
Where:
P1 = initial pressure
V1 = initial volume
P2 = new pressure
V2 = new volume
Let's substitute the given values into the formula:
(1.08 atm) × (162.2 mL) = (1.08 atm × 1.25) × V2
Now, we can solve for V2:
(1.08 atm) × (162.2 mL) = (1.35 atm) × V2
V2 = (1.08 atm × 162.2 mL) / (1.35 atm)
V2 ≈ 857.2 mL
Therefore, the new volume when the piston is depressed, increasing the pressure by 25%, is approximately 857.2 mL.