The 90 men that visited a restaurant take one of either pounded yam,rice and amala.10 take pounded yam and rice,19 take rice and amala and 29 take pounded yam and amala.x men take all the three menu.2x men each take only one food item.how many take all three food item

(x-10)+(x-19) +(x-29) +x =90

4x-58=90
4x=90+58
4x=148
x=148/4
x=37

Please represent in a Venn diagram

The answer is 8 Since rice only =poundo only=amala only=2x then 2x+2x+2x+29-x+19-x+10-x+x=90 4x+58=90 4x=90-58 4x=32=>x=8

ADEDOYIN FEYISARA OLALERE,

You did not capture the number of those that take only one food item... I.e the supposed 2x in your algorithm.
Can you relate ?

The correct answer is 8.If you add all the values in the ven diagram it will give you 90.

4x+58=90

I don't think the answer is 37 because if u sum everything within d Venn diagram it must give 90 , so 8 should b d correct answer .

The answer is 8. Because (2x x 3) + (10-x) + (29-x) + (19+x) + x = 90

This implies, 4x = 32
x = 8.

The answer is 8

2x+2x+2x+29-x+19-x+10-x+x=90
4x+58=90
4x=90-58=32
Divide both sides by 4
4x/4=32/
=8//

37