A gas at 61°C occupies a volume of 0.67 L. At what Celsius temperature will the volume increase to 1.12 L?
V1/T1 = V2/T2
Remember T must be in kelvin.
this is what i got 273.0022467
is that right
No that isn't right and I don't know how you obtained that.
For converting to kelvin, it is 61+273 (61+273.15 if you want to be exact about it). Now you plug those values in to the formula I gave you and solve for T2. The answer will be in kelvin.
To solve this problem, we can use Charles's Law, which states that at a constant pressure, the volume of a gas is directly proportional to its temperature in Kelvin.
Step 1: Convert the given temperature from Celsius to Kelvin.
To convert Celsius to Kelvin, we need to add 273.15 to the temperature.
Given temperature: 61°C
Temperature in Kelvin: 61 + 273.15 = 334.15 K
Step 2: Set up a proportion using Charles's Law.
According to Charles's Law, the volume and temperature are directly proportional. We can set up a proportion as follows:
V1 / T1 = V2 / T2
Where:
V1 = initial volume (0.67 L)
T1 = initial temperature in Kelvin (334.15 K)
V2 = final volume (1.12 L)
T2 = final temperature (unknown)
Step 3: Solve for T2.
Using the proportion above, we can solve for T2:
V1 / T1 = V2 / T2
T2 = (T1 * V2) / V1
Plugging in the values:
T2 = (334.15 K * 1.12 L) / 0.67 L
Step 4: Calculate the final temperature (T2).
T2 = 559.5485 K
Step 5: Convert the final temperature from Kelvin to Celsius.
To convert Kelvin to Celsius, subtract 273.15 from the temperature.
Final temperature in Celsius = T2 - 273.15
Final temperature in Celsius = 559.5485 - 273.15 = 286.3985°C
Therefore, at a Celsius temperature of approximately 286.4°C, the volume will increase to 1.12 L.