The spinner is divided into equal parts 1, 3, 4, 2. IF you spin it twice, what is the probability that you get a prime number. Explain please.
3/4
yeah but how
Which of those four numbers are prime?
2 and 3
You're right. I was wrong.
Since only two of those numbers are prime, then you have 1/2 a chance of getting a prime number.
no but the answer is 3/4.. It aslo says spins the wheel two times
To find the probability of getting a prime number when spinning the spinner twice, we first need to identify the prime numbers in the given options.
Prime numbers are numbers greater than 1 that can only be divided by 1 and themselves without leaving a remainder. In this case, the prime numbers are 2 and 3.
Now, let's identify the total number of possible outcomes when spinning the spinner twice. Since there are four equal parts on the spinner, the total number of outcomes is 4 multiplied by 4, which equals 16.
Next, let's determine the possible outcomes that result in a prime number. The spinner is divided into 1, 3, 4, and 2. Out of these options, only the numbers 2 and 3 are prime.
When spinning the spinner twice, you have the possibility of getting any of the four options on the first spin, and the same four options on the second spin.
To find the probability of getting a prime number on both spins, you need to calculate the probability of getting a prime number on the first spin and multiply it by the probability of getting a prime number on the second spin.
The probability of getting a prime number on the first spin is 2 (the number of prime numbers) divided by 4 (the total number of options), which simplifies to 1/2.
Similarly, the probability of getting a prime number on the second spin is also 1/2.
To find the probability of both events occurring (getting a prime number on both spins), multiply the probabilities together:
(1/2) * (1/2) = 1/4
Therefore, the probability of getting a prime number when spinning the spinner twice is 1/4, or 25%.