Consider a plane pulling up from a downward dive. If the plane has a speed of 85 m/s at the bottom of the dive and the radius of curvature of the dive is 240 m, what is the normal force on
a 78 kg pilot at the bottom of the dive?
A. 770 N
B. 790 N
C. 1600 N
D. 2300 N
E. 3100 N
What is mass*(v^2/r + g) ?
To find the normal force on the pilot at the bottom of the dive, we can use the concept of centripetal force.
In this scenario, the centripetal force is provided by the normal force of the plane pushing up on the pilot. The centripetal force equation is given by:
F = (mv^2) / r
Where:
- F is the centripetal force
- m is the mass of the pilot
- v is the speed of the plane
- r is the radius of curvature of the dive
Plugging in the given values, we have:
F = (78 kg) * (85 m/s)^2 / 240 m
Calculating this using a calculator, we get:
F ≈ 2337 N
Therefore, the normal force on the pilot at the bottom of the dive is approximately 2337 N.
Looking at the answer choices, the closest option is:
D. 2300 N
Therefore, the correct answer is D. 2300 N.