A marble at rest is dropped from the top of a building. Find the marble’s velocity after it has fallen for 3 s.
Ignore air resistance.
Use the formula: v = g x t, where v = average velocity, g = acceleration due to gravity and t = time
what is 9.8m/s^2 * 3 sec ?
To find the marble's velocity after it has fallen for 3 seconds, we can use the formula v = g x t, where v is the average velocity, g is the acceleration due to gravity, and t is the time.
First, we need to determine the value of g, which is the acceleration due to gravity. On Earth, the standard value for g is approximately 9.8 meters per second squared (m/s^2).
Now, we can plug in the values into the formula: v = 9.8 m/s^2 x 3 s = 29.4 m/s.
Therefore, the marble's velocity after falling for 3 seconds is 29.4 m/s.