Before an election,

23% said they would vote for A
9% said they would vote for B
20% said they would not vote.

These all voted as they said.
The rest of the population voted for A and B in the ratio 1:2

Who got the most votes?

Thanks to anyone who can answer.

100-23-9-20 = 48% That voted for A and B in ratio of 1:2.

A/B = 1/2. B = 2A.
A + B = 48%.
A + 2A = 48, A = 16%, B = 2A = 32%.

A = 23 + 16 = 39% Total.

B = 9 + 32 = 41% Total.

To determine who got the most votes, we first need to calculate the number of votes for each candidate.

Let's assume there are 100 people in the population, as it will make calculations easier.

Based on the given percentages, we can calculate the number of votes as follows:

Votes for candidate A = 23% of 100 = 23 votes
Votes for candidate B = 9% of 100 = 9 votes
Votes for "not voting" = 20% of 100 = 20 votes

Next, we need to calculate the votes for candidates A and B in the 1:2 ratio.

Let's assume the number of votes for candidate A in the ratio is x. Therefore, the number of votes for candidate B would be 2x based on the given ratio.

So, the total number of votes for candidate A and B would be:

Total votes for candidate A = votes for candidate A + votes for candidate B = 23 + x
Total votes for candidate B = 2x

Now, let's consider that the sum of votes for all candidates should equal the total population, which is 100:

Total votes for candidate A + Total votes for candidate B + Votes for "not voting" = 100

(23 + x) + (2x) + 20 = 100
23 + 3x + 20 = 100
43 + 3x = 100
3x = 100 - 43
3x = 57
x = 57 / 3
x = 19

Now we have the number of votes for candidate A as 23 + x = 23 + 19 = 42 votes. Additionally, the number of votes for candidate B is 2x = 2 * 19 = 38 votes.

Therefore, candidate A received 42 votes, and candidate B received 38 votes.

Comparing the votes, we can conclude that candidate A got the most votes.