# Math1

posted by Jordan

You buy a new computer for \$2100. The computer is decreases by 5% annually. When will the computer have a value of \$600?

Y = a(1+r/n)^n(t)

1. Jordan

Y = 5.25

2. Steve

You want t years, where

2100(0.95)^t = 600
0.95^t = 2/7
t = log(2/7)/log(0.95) = 24.42

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