Parabola x^2+10x+4y29=0 in standard form
4y29
??????
Was expecting a something in terms of y
I will assume a typo, and work with
x^2+10x+4y+9 = 0
That may not be what you had in mind, but you can follow the method using your corrected equation.
x^2+10x+4y+9 = 0
4y = -x^2-10x-9
y = -1/4 x^2 - 5/2 x - 9/4
To write the equation of a parabola in standard form, we need to convert the given equation into the form "y = ax^2 + bx + c".
Let's start by rearranging the equation:
x^2 + 10x + 4y = -29
To isolate the y term, we can move the x terms to the right-hand side:
4y = -x^2 - 10x - 29
Now, divide everything by 4 to isolate y:
y = (-1/4)x^2 - (10/4)x - (29/4)
Simplifying the coefficients, we have:
y = -0.25x^2 - 2.5x - 7.25
Therefore, the standard form of the given parabola equation is: y = -0.25x^2 - 2.5x - 7.25.