Bacteria can multiply at alarming rate when each bacteria splits into two new cells , thus doubling. If we start with only one bacteria which can double every hour , how many bacteria will have by the end of one day?
To determine the number of bacteria at the end of one day, we need to calculate the number of times a bacteria doubles in 24 hours.
Since each bacterium doubles every hour, after 1 hour, there will be 2 bacteria (1 x 2).
After 2 hours, there will be 4 bacteria (2 x 2).
After 3 hours, there will be 8 bacteria (4 x 2).
We can observe a pattern that the number of bacteria doubles each hour. Therefore, the number of bacteria at the end of the day can be calculated by using the formula: number of bacteria = initial number of bacteria x 2^(number of hours).
In this case, we have:
Initial number of bacteria = 1
Number of hours in a day = 24
Number of bacteria = 1 x 2^(24)
Number of bacteria = 1 x 16,777,216
Number of bacteria = 16,777,216
So, by the end of one day, there will be approximately 16,777,216 bacteria.
To find out the number of bacteria at the end of one day, we need to calculate the number of times the original bacteria doubles in one day.
Since the original bacteria doubles every hour, after 1 hour, we will have 2 bacteria (1 original + 1 new).
After 2 hours, we will have 4 bacteria (2 originals + 2 new).
After 3 hours, we will have 8 bacteria (4 originals + 4 new).
This doubling process continues for each hour. So, at the end of 24 hours, we will have:
2^24 = 16,777,216 bacteria.
Therefore, by the end of one day, starting with only one bacteria that can double every hour, we will have 16,777,216 bacteria.
furmula for 24*2
48
Since the bacteria is doubling every hour, it won't be multiplying by 2. So 24 times 2 won't be the formula.
Instead you would square it. doubles so 2^24.