Post a New Question

Science

posted by .

A reaction has a standard free-energy change of –11.70 kJ mol–1 (–2.796 kcal mol–1). Calculate the equilibrium constant for the reaction at 25 °C. Im so lost please help

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Chemistry

    The standard free energy of activation of one reaction is 94.3 kj/mol^-1 (22.54 kcal/mol^-1). The standard free energy of activation for another reaction is 76.4 kJ/mol^-1 (18.26 kcal/mol^-1). Assume temp of 298K and 1 M conc. By what …
  2. CHEMISTRY!! NEED IMMEDIATE HELP PLEASE!!!

    a. Calculate the delta H, delta G, and equilibrium constant for the reaction of methane with Cl2 to give CH3Cl and HCl. Use the following information for your calculations: Bond Dissociation Energies: CH3-H (104.8kcal/mol), Cl-Cl(59.0 …
  3. Chemistry

    A reaction has a standard free-energy change of -11.80 kJ/mol (-2.820 kcal/mol). Calculate the equilibrium constant for the reaction at 25 degrees C. Please help!
  4. Chemistry

    the standard free energy change for a chemical reaction is +13.3 kj/ mol. What is the equilibrium constant for the reaction at 125 degree C ?
  5. Chemistry

    A reaction has a standard free-energy change of –12.40 kJ mol–1 (–2.964 kcal mol–1). Calculate the equilibrium constant for the reaction at 25 °C.
  6. Chemistry

    The standard free energy of activation of a reaction A is 88.6 kJ mol–1 (21.2 kcal mol–1) at 298 K. Reaction B is one hundred million times faster than reaction A at the same temperature. The products of each reaction are 10.0 …
  7. chemistry

    The standard free energy of activation of a reaction A is 78.2 kJ mol–1 (18.7 kcal mol–1) at 298 K. Reaction B is ten million times faster than reaction A at the same temperature. The products of each reaction are 10.0 kJ mol–1 …
  8. Chemistry

    A reaction has a standard free-energy change of –10.30 kJ mol–1 (–2.462 kcal mol–1). Calculate the equilibrium constant at 25ºC.?
  9. Chemistry

    A reaction has a standard free-energy change of –12.40 kJ mol–1 (–2.964 kcal mol–1). Calculate the equilibrium constant for the reaction at 25 °C.
  10. Chemistry

    The standard free energy of activation of a reaction A is 73.4 kJ mol–1 (17.5 kcal mol–1) at 298 K. Reaction B is one million times faster than reaction A at the same temperature. The products of each reaction are 10.0 kJ mol–1 …

More Similar Questions

Post a New Question