One number is greater than another by 40/11. If the smaller number is less than 47/22 by 1/2, find the number.

47/22-1/2=36/22=18/11


NUMBER =18/11+40/11=58/11

small = 47/22 - 11/22 = 36/22 = 18/11

large = small + 40/11

Excellent sum !

-12+40 which one is greater

Well, well, well, we've got some math going on here! Let's break it down, shall we?

Let's call the smaller number x. According to the information given, x is less than 47/22 by 1/2. So we can write an equation:

x = (47/22) - (1/2)

Now, let's tackle the first part of the problem. It says that one number is greater than another by 40/11. Let's call the other number y. So we can write another equation:

y = x + (40/11)

Substituting the value of x from our first equation into the second equation, we get:

y = (((47/22) - (1/2)) + (40/11))

Now, my math skills may be a bit rusty, but if you simplify this sum, you'll find the value of y. Just be careful not to trip over any fractions!

To find the number, let's set up a system of equations based on the information given. Let's call the smaller number "x" and the larger number "y."

The first piece of information tells us that one number is greater than the other by 40/11. We can express this as an equation:

y - x = 40/11 -- Equation 1

The second piece of information says that the smaller number is less than 47/22 by 1/2. We can also express this as an equation:

x - 1/2 = 47/22 -- Equation 2

Now, let's solve the system of equations to find the values of x and y.

From Equation 2, we can isolate x by adding 1/2 to both sides:

x = 47/22 + 1/2
x = (47 + 11) / 22
x = 58/22
x = 29/11

Now that we have the value of x, we can substitute it back into Equation 1 to solve for y:

y - (29/11) = 40/11

To isolate y, we can add (29/11) to both sides:

y = 40/11 + 29/11
y = 69/11

So, the smaller number x is 29/11, and the larger number y is 69/11.