Under the same condition temperature and pressure hydrogen diffuses 8 times as fast as gas y calculate the rmm of gas y the rmm of h=2
rate for y = 1
rate for H2 = 8
(rate H2/rate y) = sqrt(mm y/mmH2)
Substitute and solve for mm y.
Where is the answer
To calculate the relative molecular mass (RMM) of gas Y, we need to use Graham's Law of Diffusion. Graham's Law of Diffusion states that the rate of diffusion of a gas is inversely proportional to the square root of its molar mass.
Given that hydrogen (H2) diffuses 8 times as fast as gas Y under the same conditions of temperature and pressure, we can set up the following equation:
Rate of diffusion of H2 / Rate of diffusion of gas Y = √(Molar mass of gas Y / Molar mass of H2)
Let's denote the molar mass of gas Y as M and the molar mass of hydrogen as 2 (since the molar mass of H2 is given as 2 g/mol).
Using the given information, we have:
8 / 1 = √(M / 2)
Squaring both sides of the equation, we get:
64 = M / 2
Multiply both sides of the equation by 2 to isolate M:
128 = M
Therefore, the relative molecular mass (RMM) of gas Y is 128 g/mol.