Two Children,A and B, fire identical 10g ball bearing from a catapult. The elastic band of each catapult is elastically extended by 0.10m and then released to fire a the ball bearings.
Child A's elastic band has a spring constant of 144 N/m. Calculate the energy transferred to the kinetic energy store of child A's ball bearing. Use an equation from the equation List.
Energy=...............................J
[2]
The initial speed of child b's ball bearing is twice as fast as childs a's ball bearing calculate the spring constant of child b's elastic band. give answer to 2 significant figures
(1/2) k x^2 = (1/2)(144)(.01) Joules
To calculate the energy transferred to the kinetic energy store of Child A's ball bearing, you can use the equation for elastic potential energy:
Elastic potential energy = 0.5 * k * x^2
Where:
- Elastic potential energy is the energy stored in the elastic material (in this case, the elastic band)
- k is the spring constant, which is given as 144 N/m
- x is the extension of the elastic band, which is given as 0.10 m
Plugging in the given values into the equation:
Elastic potential energy = 0.5 * 144 N/m * (0.10 m)^2
= 0.5 * 144 N/m * 0.01 m^2
= 0.5 * 1.44 N * m
= 0.72 N * m
= 0.72 J
Therefore, the energy transferred to the kinetic energy store of Child A's ball bearing is 0.72 joules (J).