A truck of mass 2000 kg moving on a highway experience an average frictional force 800 N. il its speed increase from 25m / s to 35m/s over a distance of 500m. What is the force generated by truck

Vo = 25 m/s.

V = 35 m/s.
d = 500 m.
Fk = 800 N.

V^2 = Vo^2 + 2a*d.
35^2 = 25^2 + 2a*500. a = ?.
35^2-25^2 = 1000a, a = 0.6 m/s^2.

F-Fk = M*a. F = ?.

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To find the force generated by the truck, we need to use Newton's second law of motion, which states that the net force acting on an object is equal to its mass multiplied by its acceleration.

First, let's calculate the acceleration of the truck. We can use the following equation of motion:

v^2 = u^2 + 2as

where:
v = final velocity = 35 m/s
u = initial velocity = 25 m/s
a = acceleration
s = distance = 500 m

Rearranging the equation, we get:

a = (v^2 - u^2) / (2s)

Plugging in the given values, we have:

a = (35^2 - 25^2) / (2 * 500)
= (1225 - 625) / 1000
= 600 / 1000
= 0.6 m/s^2

Now, we can plug the acceleration value into Newton's second law to find the force generated by the truck:

F = ma

F = 2000 kg * 0.6 m/s^2
= 1200 N

Therefore, the force generated by the truck is 1200 Newtons.