a car is used to move a crest of mass of 645kg on a horizontal road the horizontal force exerted is 15000n the coefficient of kinetic friction is 0.8 calculate the acceleration of the car

1 answer

Mg = 645 9.8 = 6321 N. = Wt. of of the mass. = Normal force, Fn.

Fex = 15,000 N.

Fk = u*Fn = 0.8 * 6321 = 5057 N. = Force of kinetic friction.

Fex-Fk = M*a. a = ?.

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a car is used to move a crest of mass of 645kg on a horizontal road the horizontal force exerted is 15000n the coefficient of kinetic friction is 0.8 calculate the acceleration of the car

M*g = 645 * 9.8 = 6321 N. = Wt. of of the mass. = Normal force, Fn.

Mg = 645 9.8 = 6321 N. = Wt. of of the mass. = Normal force, Fn.