in a neutralization reaction, dilute tetraoxosulphate (vi) acid completely reacted with sodium hydroxide solution.write a balanced chemical equation for the reaction
I GUESS that weird name you have above is sulfuric acid.
H2SO4 + 2NaOH ==> Na2SO4 + 2H2O
To write a balanced chemical equation for the reaction between dilute tetraoxosulphate (VI) acid (H2SO4) and sodium hydroxide solution (NaOH), we need to combine the ions and ensure that the number of atoms and charges are balanced on both sides of the equation.
The chemical formula for tetraoxosulphate (VI) acid is H2SO4, which means it contains two hydrogen ions (H+), one sulphate ion (SO4^2-), and four oxygen atoms (O). The chemical formula for sodium hydroxide is NaOH, which consists of one sodium ion (Na+) and one hydroxide ion (OH-).
The reaction between H2SO4 and NaOH can be represented by the following balanced chemical equation:
H2SO4 + 2NaOH -> Na2SO4 + 2H2O
In this equation, two molecules of sodium hydroxide react with one molecule of tetraoxosulphate (VI) acid to produce one molecule of sodium tetraoxosulphate (VI) (also known as sodium sulphate) and two molecules of water.
To balance the equation, we ensure that the number of atoms and charges are equal on both sides. We see that the equation is balanced with two hydrogen atoms, one sulphur atom, seven oxygen atoms, one sodium atom, and one hydroxide ion on both sides.
Thus, the balanced chemical equation for the neutralization reaction between H2SO4 and NaOH is:
H2SO4 + 2NaOH -> Na2SO4 + 2H2O