J is the set of all fractions in the form of a/(a)square where a cannot not equal to 0
Column A: a (any member of set J)
Column B: 1
A. Quantity in column A is greater
B. Quantity in column B is greater
C. two quantities in both columns are equal
D. relationship cannot be determined from information given
Answer I know is given as C. that both columns are equal as whatever value you use as "a" will result in column a being equal to 1.
Do not understand why this is
If you use a fraction such as 1/2 you will get 2. Right?
If you use 1 then only you will get 1 as the resulting answer.
Is a in column one equal to the whole (a/(a)square) result or just a (whatever number you choose) ?
How can it be that the answer is 1 no matter what number you use how large or even fractional?
Please help
Thanks!
I think real answer is D since
-if you use fraction for a the value is larger than 1
-if you use number larger than 1 for a then the value gets smaller than 1
-if you use 1 both columns are equal
In the given problem, the set J consists of all fractions in the form of a/(a)^2, where a cannot be equal to 0.
Let's understand how the values in column A are calculated. The expression a/(a)^2 can be simplified as 1/a.
Now, let's evaluate column A for different values of a:
1. For a = 1, column A would be 1/1 = 1.
2. For a = 2, column A would be 1/2.
3. For a = 3, column A would be 1/3.
4. And so on...
As you correctly pointed out, if you use a fraction such as 1/2, column A would be 1/(1/2) = 2, not 1. So, the answer should not be C.
However, there might be an error in the way the problem is presented. If the expression in column A is supposed to be (a)^2/(a)^2 instead of a/(a)^2, then the value in column A would indeed be equal to 1 for any non-zero value of a.
Please double-check the problem statement and ensure there are no discrepancies.