How many grams of NaOH will be needed to prepare 250ml of 0.1M solution:-
Mass NaOH = (1L / 1000 mL) ( 250 mL} ( 40 g / 1 mol) ( 0.1 mol / 1L) = 1 gram
To determine how many grams of NaOH are needed to prepare a 250 ml 0.1M solution, we can follow a step-by-step process:
Step 1: Understand the given information.
- Concentration of the solution (Molarity): 0.1M
- Volume of the solution: 250 ml
Step 2: Recall the formula for molarity.
Molarity (M) = moles of solute / volume of solution (in liters)
Step 3: Convert the given volume from milliliters to liters.
250 ml = 250/1000 = 0.25 liters
Step 4: Rewrite the molarity formula.
0.1M = Moles of NaOH / 0.25 liters
Step 5: Rearrange the formula to solve for moles of NaOH.
Moles of NaOH = 0.1M * 0.25 liters
Step 6: Calculate the moles of NaOH.
Moles of NaOH = 0.025 moles
Step 7: Use the molar mass of NaOH to convert moles to grams.
The molar mass of NaOH is 40 grams/mole (as Na = 23g/mol, O = 16g/mol, H = 1g/mol).
Step 8: Calculate the grams of NaOH needed.
Grams of NaOH = Moles of NaOH * Molar mass of NaOH
Grams of NaOH = 0.025 moles * 40 grams/mole
Therefore, you will need 1 gram (0.025 * 40) of NaOH to prepare 250 ml of 0.1M NaOH solution.