In a plan for area codes, the first digit could be any number from 2 through 8, the second digit was either 0 or 1, and the third digit could be any number except 0. With this plan, how many different area codes were possible?
My answer: 7*8*2=112
how about 7*2*9 ?
Your answer is incorrect. To find the total number of possible area codes, we need to multiply the number of choices for each digit.
First Digit: There are 7 possible choices (2 through 8).
Second Digit: There are 2 possible choices (0 or 1).
Third Digit: There are 9 possible choices (any number except 0).
To calculate the total number of possible area codes, we multiply the number of choices for each digit:
7 * 2 * 9 = 126
Therefore, there are 126 different possible area codes.
To calculate the number of possible area codes, you need to consider the range of options for each digit and multiply them together.
For the first digit, you are given that it can be any number from 2 through 8. So, there are 7 possible options for the first digit (8 - 2 + 1 = 7).
For the second digit, it can be either 0 or 1. So, there are 2 possible options for the second digit.
For the third digit, it can be any number except 0. So, there are 9 possible options for the third digit (since 0 is excluded).
To find the total number of possible area codes, you multiply the number of options for each digit: 7 * 2 * 9 = 126.
Therefore, there are 126 different possible area codes.