Math - Trig

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Two buildings of equal height are 850 feet apart. An observer on the street between the buildings measures the angles of elevation to the tops of the buildings as 29° and 40°. How​ high, to the nearest​ foot, are the​ buildings?

I don't know how to set this up

  • Math - Trig -

    x and 850 -x

    tan 29 = h/x so x = 1.804 h

    tan 40 = h/(850-x)= .8391
    h = (850 -1.804h)(.8391)

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